basic values and types

calculate 2+8 and put the result in tha variable x.
- print the value of x
  
  hint: use the function print()
- what is the type of x?
  
  hint: use the function type()
calculate 5 / 2 and put the result in the variable y. print y and the type of y
put "hello world" into a variable named greeting.
- print the variable and the type of the variable
- what is the len of greeting?
  
  hint: use the function len()
put the values 1, 2 and 3 into list1 and the values "a", "b" and "c" into list2.
- calcluate list1 + list2 and put the result into list3
- print list3
- print the type of list3
- print the len of list3

# 1
x = 2 + 8
print(type(x), x)

# 2
y = 5/2
print(type(y), y)

# 3
greeting = "hello world"
print(type(greeting), greeting)
print(len(greeting))

# 4
list1 = [1,2,3]
list2 = ["a", "b", "c"]
list3 = list1 + list2
print(type(list3), list3)
print(len(list3))

<class 'int'> 10
<class 'float'> 2.5
<class 'str'> hello world
11
<class 'list'> [1, 2, 3, 'a', 'b', 'c']
6

getting help

suppose we want to understand how to use a function. we can use the help() function for that!

let’s try to use the function str.upper(), by copying this code below and running it:
```
print( "hello".upper() )
```
lets see how to get help for a function. type the following code into a cell below. this will explain what the function str.upper does
```
help("hello".upper)
```

# 1
print( "hello".upper() )

# 2
help("hello".upper)

HELLO
Help on built-in function upper:

upper() method of builtins.str instance
    Return a copy of the string converted to uppercase.

some simple string functions

lets get help for all the cool functions the type str has. lets call help(str). run the following code:
```
help(str)
```
read the documentation you’ve just printed, for the following functions: lower, upper, title, islower, isupper and try to figure out what they do. you can try to use them, read the documentation again, google for them. anything that helps you understand.
convert this string to uppercase "the quick brown fox jumped over the lazy dog"

hint: use one of the functions you’ve learned in question #2
is the string "I JusT mEt YoU, anD tHIs is CraaZy, sO CAll mE mayBe" in lower case? can you convert it to lower case?
hints :
1. there is a function that checks if a string is lower case
2. there is a function that converts a string to lower case

# 1
help(str)

# 3
sentence = "the quick brown fox jumped over the lazy dog"
print(sentence.upper())

# 4
crazy = "I JusT mEt YoU, anD tHIs is CraaZy, sO CAll mE mayBe"
print()
print("is lower? " , crazy)
print(crazy.islower())
print()
print("is lower? ", crazy.lower())
print(crazy.lower().islower())

Help on class str in module builtins:

class str(object)
 |  str(object='') -> str
 |  str(bytes_or_buffer[, encoding[, errors]]) -> str
 |  
 |  Create a new string object from the given object. If encoding or
 |  errors is specified, then the object must expose a data buffer
 |  that will be decoded using the given encoding and error handler.
 |  Otherwise, returns the result of object.__str__() (if defined)
 |  or repr(object).
 |  encoding defaults to sys.getdefaultencoding().
 |  errors defaults to 'strict'.
 |  
 |  Methods defined here:
 |  
 |  __add__(self, value, /)
 |      Return self+value.
 |  
 |  __contains__(self, key, /)
 |      Return key in self.
 |  
 |  __eq__(self, value, /)
 |      Return self==value.
 |  
 |  __format__(self, format_spec, /)
 |      Return a formatted version of the string as described by format_spec.
 |  
 |  __ge__(self, value, /)
 |      Return self>=value.
 |  
 |  __getattribute__(self, name, /)
 |      Return getattr(self, name).
 |  
 |  __getitem__(self, key, /)
 |      Return self[key].
 |  
 |  __getnewargs__(...)
 |  
 |  __gt__(self, value, /)
 |      Return self>value.
 |  
 |  __hash__(self, /)
 |      Return hash(self).
 |  
 |  __iter__(self, /)
 |      Implement iter(self).
 |  
 |  __le__(self, value, /)
 |      Return self<=value.
 |  
 |  __len__(self, /)
 |      Return len(self).
 |  
 |  __lt__(self, value, /)
 |      Return self<value.
 |  
 |  __mod__(self, value, /)
 |      Return self%value.
 |  
 |  __mul__(self, value, /)
 |      Return self*value.
 |  
 |  __ne__(self, value, /)
 |      Return self!=value.
 |  
 |  __repr__(self, /)
 |      Return repr(self).
 |  
 |  __rmod__(self, value, /)
 |      Return value%self.
 |  
 |  __rmul__(self, value, /)
 |      Return value*self.
 |  
 |  __sizeof__(self, /)
 |      Return the size of the string in memory, in bytes.
 |  
 |  __str__(self, /)
 |      Return str(self).
 |  
 |  capitalize(self, /)
 |      Return a capitalized version of the string.
 |      
 |      More specifically, make the first character have upper case and the rest lower
 |      case.
 |  
 |  casefold(self, /)
 |      Return a version of the string suitable for caseless comparisons.
 |  
 |  center(self, width, fillchar=' ', /)
 |      Return a centered string of length width.
 |      
 |      Padding is done using the specified fill character (default is a space).
 |  
 |  count(...)
 |      S.count(sub[, start[, end]]) -> int
 |      
 |      Return the number of non-overlapping occurrences of substring sub in
 |      string S[start:end].  Optional arguments start and end are
 |      interpreted as in slice notation.
 |  
 |  encode(self, /, encoding='utf-8', errors='strict')
 |      Encode the string using the codec registered for encoding.
 |      
 |      encoding
 |        The encoding in which to encode the string.
 |      errors
 |        The error handling scheme to use for encoding errors.
 |        The default is 'strict' meaning that encoding errors raise a
 |        UnicodeEncodeError.  Other possible values are 'ignore', 'replace' and
 |        'xmlcharrefreplace' as well as any other name registered with
 |        codecs.register_error that can handle UnicodeEncodeErrors.
 |  
 |  endswith(...)
 |      S.endswith(suffix[, start[, end]]) -> bool
 |      
 |      Return True if S ends with the specified suffix, False otherwise.
 |      With optional start, test S beginning at that position.
 |      With optional end, stop comparing S at that position.
 |      suffix can also be a tuple of strings to try.
 |  
 |  expandtabs(self, /, tabsize=8)
 |      Return a copy where all tab characters are expanded using spaces.
 |      
 |      If tabsize is not given, a tab size of 8 characters is assumed.
 |  
 |  find(...)
 |      S.find(sub[, start[, end]]) -> int
 |      
 |      Return the lowest index in S where substring sub is found,
 |      such that sub is contained within S[start:end].  Optional
 |      arguments start and end are interpreted as in slice notation.
 |      
 |      Return -1 on failure.
 |  
 |  format(...)
 |      S.format(*args, **kwargs) -> str
 |      
 |      Return a formatted version of S, using substitutions from args and kwargs.
 |      The substitutions are identified by braces ('{' and '}').
 |  
 |  format_map(...)
 |      S.format_map(mapping) -> str
 |      
 |      Return a formatted version of S, using substitutions from mapping.
 |      The substitutions are identified by braces ('{' and '}').
 |  
 |  index(...)
 |      S.index(sub[, start[, end]]) -> int
 |      
 |      Return the lowest index in S where substring sub is found, 
 |      such that sub is contained within S[start:end].  Optional
 |      arguments start and end are interpreted as in slice notation.
 |      
 |      Raises ValueError when the substring is not found.
 |  
 |  isalnum(self, /)
 |      Return True if the string is an alpha-numeric string, False otherwise.
 |      
 |      A string is alpha-numeric if all characters in the string are alpha-numeric and
 |      there is at least one character in the string.
 |  
 |  isalpha(self, /)
 |      Return True if the string is an alphabetic string, False otherwise.
 |      
 |      A string is alphabetic if all characters in the string are alphabetic and there
 |      is at least one character in the string.
 |  
 |  isascii(self, /)
 |      Return True if all characters in the string are ASCII, False otherwise.
 |      
 |      ASCII characters have code points in the range U+0000-U+007F.
 |      Empty string is ASCII too.
 |  
 |  isdecimal(self, /)
 |      Return True if the string is a decimal string, False otherwise.
 |      
 |      A string is a decimal string if all characters in the string are decimal and
 |      there is at least one character in the string.
 |  
 |  isdigit(self, /)
 |      Return True if the string is a digit string, False otherwise.
 |      
 |      A string is a digit string if all characters in the string are digits and there
 |      is at least one character in the string.
 |  
 |  isidentifier(self, /)
 |      Return True if the string is a valid Python identifier, False otherwise.
 |      
 |      Use keyword.iskeyword() to test for reserved identifiers such as "def" and
 |      "class".
 |  
 |  islower(self, /)
 |      Return True if the string is a lowercase string, False otherwise.
 |      
 |      A string is lowercase if all cased characters in the string are lowercase and
 |      there is at least one cased character in the string.
 |  
 |  isnumeric(self, /)
 |      Return True if the string is a numeric string, False otherwise.
 |      
 |      A string is numeric if all characters in the string are numeric and there is at
 |      least one character in the string.
 |  
 |  isprintable(self, /)
 |      Return True if the string is printable, False otherwise.
 |      
 |      A string is printable if all of its characters are considered printable in
 |      repr() or if it is empty.
 |  
 |  isspace(self, /)
 |      Return True if the string is a whitespace string, False otherwise.
 |      
 |      A string is whitespace if all characters in the string are whitespace and there
 |      is at least one character in the string.
 |  
 |  istitle(self, /)
 |      Return True if the string is a title-cased string, False otherwise.
 |      
 |      In a title-cased string, upper- and title-case characters may only
 |      follow uncased characters and lowercase characters only cased ones.
 |  
 |  isupper(self, /)
 |      Return True if the string is an uppercase string, False otherwise.
 |      
 |      A string is uppercase if all cased characters in the string are uppercase and
 |      there is at least one cased character in the string.
 |  
 |  join(self, iterable, /)
 |      Concatenate any number of strings.
 |      
 |      The string whose method is called is inserted in between each given string.
 |      The result is returned as a new string.
 |      
 |      Example: '.'.join(['ab', 'pq', 'rs']) -> 'ab.pq.rs'
 |  
 |  ljust(self, width, fillchar=' ', /)
 |      Return a left-justified string of length width.
 |      
 |      Padding is done using the specified fill character (default is a space).
 |  
 |  lower(self, /)
 |      Return a copy of the string converted to lowercase.
 |  
 |  lstrip(self, chars=None, /)
 |      Return a copy of the string with leading whitespace removed.
 |      
 |      If chars is given and not None, remove characters in chars instead.
 |  
 |  partition(self, sep, /)
 |      Partition the string into three parts using the given separator.
 |      
 |      This will search for the separator in the string.  If the separator is found,
 |      returns a 3-tuple containing the part before the separator, the separator
 |      itself, and the part after it.
 |      
 |      If the separator is not found, returns a 3-tuple containing the original string
 |      and two empty strings.
 |  
 |  replace(self, old, new, count=-1, /)
 |      Return a copy with all occurrences of substring old replaced by new.
 |      
 |        count
 |          Maximum number of occurrences to replace.
 |          -1 (the default value) means replace all occurrences.
 |      
 |      If the optional argument count is given, only the first count occurrences are
 |      replaced.
 |  
 |  rfind(...)
 |      S.rfind(sub[, start[, end]]) -> int
 |      
 |      Return the highest index in S where substring sub is found,
 |      such that sub is contained within S[start:end].  Optional
 |      arguments start and end are interpreted as in slice notation.
 |      
 |      Return -1 on failure.
 |  
 |  rindex(...)
 |      S.rindex(sub[, start[, end]]) -> int
 |      
 |      Return the highest index in S where substring sub is found,
 |      such that sub is contained within S[start:end].  Optional
 |      arguments start and end are interpreted as in slice notation.
 |      
 |      Raises ValueError when the substring is not found.
 |  
 |  rjust(self, width, fillchar=' ', /)
 |      Return a right-justified string of length width.
 |      
 |      Padding is done using the specified fill character (default is a space).
 |  
 |  rpartition(self, sep, /)
 |      Partition the string into three parts using the given separator.
 |      
 |      This will search for the separator in the string, starting at the end. If
 |      the separator is found, returns a 3-tuple containing the part before the
 |      separator, the separator itself, and the part after it.
 |      
 |      If the separator is not found, returns a 3-tuple containing two empty strings
 |      and the original string.
 |  
 |  rsplit(self, /, sep=None, maxsplit=-1)
 |      Return a list of the words in the string, using sep as the delimiter string.
 |      
 |        sep
 |          The delimiter according which to split the string.
 |          None (the default value) means split according to any whitespace,
 |          and discard empty strings from the result.
 |        maxsplit
 |          Maximum number of splits to do.
 |          -1 (the default value) means no limit.
 |      
 |      Splits are done starting at the end of the string and working to the front.
 |  
 |  rstrip(self, chars=None, /)
 |      Return a copy of the string with trailing whitespace removed.
 |      
 |      If chars is given and not None, remove characters in chars instead.
 |  
 |  split(self, /, sep=None, maxsplit=-1)
 |      Return a list of the words in the string, using sep as the delimiter string.
 |      
 |      sep
 |        The delimiter according which to split the string.
 |        None (the default value) means split according to any whitespace,
 |        and discard empty strings from the result.
 |      maxsplit
 |        Maximum number of splits to do.
 |        -1 (the default value) means no limit.
 |  
 |  splitlines(self, /, keepends=False)
 |      Return a list of the lines in the string, breaking at line boundaries.
 |      
 |      Line breaks are not included in the resulting list unless keepends is given and
 |      true.
 |  
 |  startswith(...)
 |      S.startswith(prefix[, start[, end]]) -> bool
 |      
 |      Return True if S starts with the specified prefix, False otherwise.
 |      With optional start, test S beginning at that position.
 |      With optional end, stop comparing S at that position.
 |      prefix can also be a tuple of strings to try.
 |  
 |  strip(self, chars=None, /)
 |      Return a copy of the string with leading and trailing whitespace remove.
 |      
 |      If chars is given and not None, remove characters in chars instead.
 |  
 |  swapcase(self, /)
 |      Convert uppercase characters to lowercase and lowercase characters to uppercase.
 |  
 |  title(self, /)
 |      Return a version of the string where each word is titlecased.
 |      
 |      More specifically, words start with uppercased characters and all remaining
 |      cased characters have lower case.
 |  
 |  translate(self, table, /)
 |      Replace each character in the string using the given translation table.
 |      
 |        table
 |          Translation table, which must be a mapping of Unicode ordinals to
 |          Unicode ordinals, strings, or None.
 |      
 |      The table must implement lookup/indexing via __getitem__, for instance a
 |      dictionary or list.  If this operation raises LookupError, the character is
 |      left untouched.  Characters mapped to None are deleted.
 |  
 |  upper(self, /)
 |      Return a copy of the string converted to uppercase.
 |  
 |  zfill(self, width, /)
 |      Pad a numeric string with zeros on the left, to fill a field of the given width.
 |      
 |      The string is never truncated.
 |  
 |  ----------------------------------------------------------------------
 |  Static methods defined here:
 |  
 |  __new__(*args, **kwargs) from builtins.type
 |      Create and return a new object.  See help(type) for accurate signature.
 |  
 |  maketrans(x, y=None, z=None, /)
 |      Return a translation table usable for str.translate().
 |      
 |      If there is only one argument, it must be a dictionary mapping Unicode
 |      ordinals (integers) or characters to Unicode ordinals, strings or None.
 |      Character keys will be then converted to ordinals.
 |      If there are two arguments, they must be strings of equal length, and
 |      in the resulting dictionary, each character in x will be mapped to the
 |      character at the same position in y. If there is a third argument, it
 |      must be a string, whose characters will be mapped to None in the result.

THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG

is lower?  I JusT mEt YoU, anD tHIs is CraaZy, sO CAll mE mayBe
False

is lower?  i just met you, and this is craazy, so call me maybe
True

input from the user

run the following code to get input from the user (you are the user!)

name = input("what is your name: ")
print("hi", name)

your programs now have the power to ask questions!

name = input("what is your name: ")
print("hi", name)

what is your name: aviad
hi aviad

BMI: Body mass index

In health the BMI (body mass index) is defined as $BMI=\frac{weight}{height^2}$

where the weight is in kilograms, and the height is in meters.

for example for weight 80kg and height 2.0m the BMI is $80 / (2^2) = 80 /4 = 20 $

put 97 into a variable called weight
put 1.84 into a variabled called height
write code to compute and print the bmi

weight = 97
height = 1.84
bmi = weight / height**2
print(bmi)

28.650756143667294

BMI with input from user

use the input() function to ask the user for his weight, put in variable weight
what is the type of the variable weight?
use the following code to convert the value to a float
```
w = float(weight)
```
what is the type of w now?
ask the user for his height and convert to float
compute and print the bmi

weight = input("what is your weight? ")
print(type(weight), weight)
w = float(weight)
print(type(w), w)
height = input("what is your height? ")
h = float(height)
bmi  = w/h**2
print(bmi)

what is your weight? 80
<class 'str'> 80
<class 'float'> 80.0
what is your height? 1.8
24.691358024691358

help for str.split() function

print the help for the function str.split

hint: use the help() function

help(str.split)

Help on method_descriptor:

split(self, /, sep=None, maxsplit=-1)
    Return a list of the words in the string, using sep as the delimiter string.
    
    sep
      The delimiter according which to split the string.
      None (the default value) means split according to any whitespace,
      and discard empty strings from the result.
    maxsplit
      Maximum number of splits to do.
      -1 (the default value) means no limit.

split a string

create the following string, and put it in a variable called sent
```
"the quick brown fox jumped over the lazy dog"
```
then split it into a list so that each word is an an element in the list.
and put the result into another variable called words
print the variable words

expected ouput:

['the', 'quick', 'brown', 'fox', 'jumped', 'over', 'the', 'lazy', 'dog']

sent = "the quick brown fox jumped over the lazy dog"
words = sent.split()
print(words)

['the', 'quick', 'brown', 'fox', 'jumped', 'over', 'the', 'lazy', 'dog']

str.join()

use the function help to read the documentation for the str.join function
read this code
```
mylist = ["one", "two", "three"]
result = " ".join(mylist)
print(result)
```
1. can you guess what this code does ?
2. what is the function join?
3. use help or documentation online if you can’t guess
4. copy this code to the cell below and run it to see if you were right

help(str.join)

# one two three
# join will add a space ' ' between each two words in mylist
mylist = ["one", "two", "three"]
result = " ".join(mylist)
print(result)

Help on method_descriptor:

join(self, iterable, /)
    Concatenate any number of strings.
    
    The string whose method is called is inserted in between each given string.
    The result is returned as a new string.
    
    Example: '.'.join(['ab', 'pq', 'rs']) -> 'ab.pq.rs'

one two three

using str.upper() and str.join()

split the sentence "the quick brown fox jumped over the lazy dog" into words using the function .split() and put the result in a variable called words .
replace the the words “dog” and “fox” in the words list with uppercase “DOG” and “FOX”

HINTS:
- use the .upper() function
- use indexing like words[3] to acccess a particular word in the words list
use the function join to convert the list back into a string
print the result

expected output:

"the quick brown FOX jumped over the lazy DOG"

words = "the quick brown fox jumped over the lazy dog".split()
# print(words)
words[3] = words[3].upper()
words[-1] = words[-1].upper()
# print(words)
result = " ".join(words)
print(result)

the quick brown FOX jumped over the lazy DOG

4 boom

in this exercise, we’re going to take some song lyrics, and replace every 4th word of each line with the word “boom”. and then print out the lyrics.

NOTE: this exercise is simple but takes a lot of lines of code. we will learn loops IN THE NEXT LESSON. loops will help us write shorter solutions, but for now YOU DONT NEED LOOPS

use the following code, which puts an important 😜 string in a variable named song

song = """
Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say good bye
Never gonna tell a lie and hurt you
"""

split this string into a list of lines. put it in variable called lines

hint: string have a function called .splitlines()
split the line 0 into words. put it in variable called words0
- now also split line 1. put it into words1
- repeat for line 2 …, line 5, put each into word1, … word5
hint: this should take you 6 simples lines.
replace the 4th word of line 1, line 2, … line 6 with the word "boom"`

hint: you don’t need loops. this again takes 6 lines
now join words0. put the result into variable boom0
- continue to join words1, words2 … words5 into boom1, boom2 … boom5
create a list that contains boom0, boom1, … boom5, call it boom
join the lines in boom back into a string. put it into a variable called result
hint: use this code
```
result = "\n".join(boom)
```
print the result

expected output:

Never gonna give you boom
Never gonna let you boom
Never gonna run around boom desert you
Never gonna make you boom
Never gonna say good boom
Never gonna tell a boom and hurt you

### useful: data
song = """Never gonna give you up
Never gonna let you down
Never gonna run around and desert you
Never gonna make you cry
Never gonna say good bye
Never gonna tell a lie and hurt you
"""

lines = song.splitlines()

words0 = lines[0].split()
words1 = lines[1].split()
words2 = lines[2].split()
words3 = lines[3].split()
words4 = lines[4].split()
words5 = lines[5].split()

words0[4] = "boom"
words1[4] = "boom"
words2[4] = "boom"
words3[4] = "boom"
words4[4] = "boom"
words5[4] = "boom"

boom0 = " ".join(words0)
boom1 = " ".join(words1)
boom2 = " ".join(words2)
boom3 = " ".join(words3)
boom4 = " ".join(words4)
boom5 = " ".join(words5)

boom = [boom0, boom1, boom2, boom3, boom4, boom5]
result = "\n".join(boom)
print(result)

Never gonna give you boom
Never gonna let you boom
Never gonna run around boom desert you
Never gonna make you boom
Never gonna say good boom
Never gonna tell a boom and hurt you

Dictionary

create a dictionary that maps the name of cheeses to prices of 100mg of that cheese.
```
 gouda costs 4.99 
 Edam costs 2.45
 Camambert costs 7.75
 Bree costs 7.27
```
without using “head math”, write simple code to compute the costs of gouda, edam and camambert together

hint: the solution is one simple but long line of code, which uses the + operator 3 times
add a new cheese to the dictionary: Cottage cheese, which costs 3.2

hint: the solution takes just one very simple line of code
the government has added a new tax on milk products, now every cheese costs has increased by 27% ! can you update the costs in the dictionary?

hint: the solution takes 5 (almost identical) lines of code
can you use the round() function to round the prices of cheese, so that it has costs in dollars and cents (Shekels and agorot)?
hint: what does the following code do?
```
 pi = 3.14159265
 print(pi)
 pi_rounded = round(pi, 2)
 print(pi_rounded)
```

# 1
print()
print(1)
print('-' * 10)
costs = {
    "Gouda" : 4.99 ,
    "Edam" : 2.45,
    "Camambert" : 7.75,
    "Bree" : 7.27
}
print(costs)

# 2
print()
print(2)
print('-' * 10)
print(costs["Gouda"] + costs["Edam"] + costs["Camambert"])

# 3
print()
print(3)
print('-' * 10)
costs["Cottage"] = 3.2
print(costs)

# 4
print()
print(4)
print('-' * 10)
costs['Gouda'] = costs['Gouda'] * 1.27
costs['Edam'] = costs['Edam'] * 1.27
costs['Camambert'] = costs['Camambert'] * 1.27
costs['Bree'] = costs['Bree'] * 1.27
costs['Cottage'] = costs['Cottage'] * 1.27
print(costs)

# 5
print()
print(5)
print('-' * 10)
pi = 3.14159265
print(pi)
pi_rounded = round(pi, 2)
print(pi_rounded)

costs['Gouda'] = round(costs['Gouda'], 2)
costs['Edam'] = round(costs['Edam'], 2)
costs['Camambert'] = round(costs['Camambert'], 2)
costs['Bree'] = round(costs['Bree'], 2)
costs['Cottage'] = round(costs['Cottage'], 2)
print(costs)

1
----------
{'Gouda': 4.99, 'Edam': 2.45, 'Camambert': 7.75, 'Bree': 7.27}

2
----------
15.190000000000001

3
----------
{'Gouda': 4.99, 'Edam': 2.45, 'Camambert': 7.75, 'Bree': 7.27, 'Cottage': 3.2}

4
----------
{'Gouda': 6.3373, 'Edam': 3.1115000000000004, 'Camambert': 9.8425, 'Bree': 9.232899999999999, 'Cottage': 4.064}

5
----------
3.14159265
3.14
{'Gouda': 6.34, 'Edam': 3.11, 'Camambert': 9.84, 'Bree': 9.23, 'Cottage': 4.06}

len and indexing

quote = "everything should be as simple as possible, but not simpler. Albert Einstein"

write code to check how many letters/characters are in this qoute.

hint: use the function len()
split this qoute into words. how many words are in this quote?
write code to print:
1. the 1st letter in the quote
2. the 7th word
3. the 1st letter of the 7th word
4. the last letter in the quote
5. the last letter of the 9th word

hint: the function len() is useful to figuring out what is the last letter/word

# 1
quote = "everything should be as simple as possible but not simpler. Albert Einstein"
print(len(quote))

# 2
words = quote.split()
print(len(words))

# 3
print(quote[0])
print(words[6]) # 7th word
print(words[6][0]) # 1st letter of 7th word
print(quote[len(quote) - 1]) #last letter
word8 = words[8] # 9th word
print(word8[len(word8) -1]) #last letter of 9th word

75
12
e
possible
p
n
t

len, indexing and input

what would the following code print? first try to answer yourself, then copy the code and run it to see if you guessed right

hi = "hello "
greeting = hi * 3
print(greeting)

use the input() function to ask the user for full name.
print the length of the name
print the last letter of the name 100 times

# 1
hi = "hello "
greeting = hi * 3
print(greeting)

name = input("what is your full name? ")
print(len(name))
print(name[len(name) -1] * 100)

hello hello hello 
what is your full name? aviad rozenhek
14
kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk